-8n^2-32n=0

Solution for -8n^2-32n=0 equation:

-8n^2-32n=0

a = -8; b = -32; c = 0;
Δ = b2-4ac
Δ = -322-4·(-8)·0
Δ = 1024
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{1024}=32$
$n_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-32)-32}{2*-8}=\frac{0}{-16}
=0
$
$n_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-32)+32}{2*-8}=\frac{64}{-16}
=-4
$